Log[2](x+3)-log[2](x-1)=5

Solution for Log[2](x+3)-log[2](x-1)=5 equation:

Simplifying
Log[2](x + 3) + -1log[2](x + -1) = 5

Reorder the terms:
goL * 2(3 + x) + -1log[2](x + -1) = 5

Reorder the terms for easier multiplication:
2goL(3 + x) + -1log[2](x + -1) = 5
(3 * 2goL + x * 2goL) + -1log[2](x + -1) = 5
(6goL + 2goxL) + -1log[2](x + -1) = 5

Reorder the terms:
6goL + 2goxL + -1glo * 2(-1 + x) = 5

Reorder the terms for easier multiplication:
6goL + 2goxL + -1 * 2glo(-1 + x) = 5

Multiply -1 * 2
6goL + 2goxL + -2glo(-1 + x) = 5
6goL + 2goxL + (-1 * -2glo + x * -2glo) = 5
6goL + 2goxL + (2glo + -2glox) = 5

Reorder the terms:
2glo + -2glox + 6goL + 2goxL = 5

Solving
2glo + -2glox + 6goL + 2goxL = 5

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-5 + 2glo + -2glox + 6goL + 2goxL = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 2glo + -2glox + 6goL + 2goxL = 0

The solution to this equation could not be determined.